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Discuss to calculate if one radiator can be added to CH system in the Plumbing Jobs | The Job-board area at PlumbersForums.net

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hussy

Hi all
I have a conventional open vented CH system with x9 radiators in a x4 bed house. The living room has one radiator and other areas of the room are cold. I want to add a radiator to this room.
How do you calculate if one can be added and is there a specific calculation/calculator to figure this.
I guess you take the width/height measurements or your radiator and note if they are single/double panel etc.
What else comes into play in the maths of this.
By the way thanks to everyone re my last thread, all fixed now.
 
if your diy, then add another rad to match the one you have , on an old ov system youll probably have more than enough power in hand on the boiler not to have to worry.
 
hi
the house is 15 yrs old, oil burner in outhouse.
I have a double panel rad 1/2 size of existing rad in living room, was going to install that from a branch off opposite a hall rad.
 
I personally would put the heating on full till everything melts. If it struggles and everything gets just warm you cant do it. If it boils the cat then you got the heatage!

I have never done it though so wait for someone more sensible there is a calculation based on heat output of the boiler KW i believe.
 
Q'est que???
ha ha ha that was one mighty weird reply, tell me more on the calculation!
 
there is a proper way to work out heat loss per room using U values and calculations. Also there is a mears calculator but this is not as accurate. Most engineers jus use their experience to know what size boiler a house requires. but this all depends on if you got double glazing, filled cavity wall or jus a cavity, roof insulation, floor insualtion and air changes.
 
like i said if your going to diy it then off you go, wont be a problem.
 
have you tried balancing the system? possibly sludged up?do you know the output of your boiler:)regards turnpin
 
the CH system has been thoroughly clean and protected. In the same houses in my street, they have x2 rads in their living rooms, which is why I was thinking of installing another one as I have only one.

Old plumber you are a bit of a sarky sort but I love the larks.
 
if these houses are all the same with identicle systems the just measure the neighbours rads.Simples:)regards turnpin
 
night all, sarkys off to bed, told you to just get on with it in my first post didnt I
 
Agree with Oldplumber. Dont confuse the situation, just add a radiator, it will be OK.
 
if your diy, then add another rad to match the one you have , on an old ov system youll probably have more than enough power in hand on the boiler not to have to worry.
+1 agree with OldPlumbers advice.
 
dear old plumber, your were right all along and all else agree. I thankyou and nighty night:p
 
there is a proper way to work out heat loss per room using U values and calculations. Also there is a mears calculator but this is not as accurate. Most engineers jus use their experience to know what size boiler a house requires. but this all depends on if you got double glazing, filled cavity wall or jus a cavity, roof insulation, floor insualtion and air changes.

its easy to calculate the size of the rad for each room but r u asking if a rad can be added without over stretching the boiler?

what is the output of the boiler? what is the outputs of all rads? whats the output of the hot water system? what sizze is the pipe going to the proposed rad? how many rads are off the pipe going to the proposed new rad?

if u can work all that out see if the boiler output is at least 15% greater than the collective outputs of all the other things. then check the pipe is big enough to send enough heat down the pipe to the rads offf that circuit
 
thanks fuzzy, i will work my way through that, and yes I was questioning this so as not too overstretch the boiler capacity. The pipes are 15mm copper, all single panel rads x5 and x4 same downstairs - need to measure though.
Thanks
 
Easy answer:

If normal room (one external wall, one window) 45, warm room (small internal or loads of insulation on external wall) 40 and cold room (two or three external walls, single glazing, large chimney, etc) 50.

Then - size of room multiplied by above number and divide by 1000 gives you the wattage required.

So 4m long x 3m wide x 2.8m tall = 33.6 x 45 / 1000 = 1.512Kw
 
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