to calculate if one radiator can be added to CH system

[turnpin]

if these houses are all the same with identicle systems the just measure the neighbours rads.Simplesregards turnpin

 

[oldplumber]

night all, sarkys off to bed, told you to just get on with it in my first post didnt I

 

[GreenArmy]

Agree with Oldplumber. Dont confuse the situation, just add a radiator, it will be OK.

 

[Blackcatgas]

if your diy, then add another rad to match the one you have , on an old ov system youll probably have more than enough power in hand on the boiler not to have to worry.

+1 agree with OldPlumbers advice.

 

[hussy]

dear old plumber, your were right all along and all else agree. I thankyou and nighty night

 

[fuzzy]

there is a proper way to work out heat loss per room using U values and calculations. Also there is a mears calculator but this is not as accurate. Most engineers jus use their experience to know what size boiler a house requires. but this all depends on if you got double glazing, filled cavity wall or jus a cavity, roof insulation, floor insualtion and air changes.

its easy to calculate the size of the rad for each room but r u asking if a rad can be added without over stretching the boiler?

what is the output of the boiler? what is the outputs of all rads? whats the output of the hot water system? what sizze is the pipe going to the proposed rad? how many rads are off the pipe going to the proposed new rad?

if u can work all that out see if the boiler output is at least 15% greater than the collective outputs of all the other things. then check the pipe is big enough to send enough heat down the pipe to the rads offf that circuit

 

[hussy]

thanks fuzzy, i will work my way through that, and yes I was questioning this so as not too overstretch the boiler capacity. The pipes are 15mm copper, all single panel rads x5 and x4 same downstairs - need to measure though.
Thanks

 

[dontknowitall]

Easy answer:

If normal room (one external wall, one window) 45, warm room (small internal or loads of insulation on external wall) 40 and cold room (two or three external walls, single glazing, large chimney, etc) 50.

Then - size of room multiplied by above number and divide by 1000 gives you the wattage required.

So 4m long x 3m wide x 2.8m tall = 33.6 x 45 / 1000 = 1.512Kw